4(x^2+1)=2(x^2-3)+2

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Solution for 4(x^2+1)=2(x^2-3)+2 equation:


Simplifying
4(x2 + 1) = 2(x2 + -3) + 2

Reorder the terms:
4(1 + x2) = 2(x2 + -3) + 2
(1 * 4 + x2 * 4) = 2(x2 + -3) + 2
(4 + 4x2) = 2(x2 + -3) + 2

Reorder the terms:
4 + 4x2 = 2(-3 + x2) + 2
4 + 4x2 = (-3 * 2 + x2 * 2) + 2
4 + 4x2 = (-6 + 2x2) + 2

Reorder the terms:
4 + 4x2 = -6 + 2 + 2x2

Combine like terms: -6 + 2 = -4
4 + 4x2 = -4 + 2x2

Solving
4 + 4x2 = -4 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
4 + 4x2 + -2x2 = -4 + 2x2 + -2x2

Combine like terms: 4x2 + -2x2 = 2x2
4 + 2x2 = -4 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
4 + 2x2 = -4 + 0
4 + 2x2 = -4

Add '-4' to each side of the equation.
4 + -4 + 2x2 = -4 + -4

Combine like terms: 4 + -4 = 0
0 + 2x2 = -4 + -4
2x2 = -4 + -4

Combine like terms: -4 + -4 = -8
2x2 = -8

Divide each side by '2'.
x2 = -4

Simplifying
x2 = -4

Reorder the terms:
4 + x2 = -4 + 4

Combine like terms: -4 + 4 = 0
4 + x2 = 0

The solution to this equation could not be determined.

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